Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 14 feet and a height of 8 feet. Container B has a diameter of 8 feet and a height of 17 feet. Container A is full of water and the water is pumped into Container B until Container B is completely full.
After the pumping is complete, what is the volume of water remaining in Container A, to the nearest tenth of a cubic foot?
amazing. You got
A = 1231.5
B = 904.8
Then you blew it, by thinking that all of A was pumped into B. Rather, the problem clearly stated that "Container A is full of water and the water is pumped into Container B until Container B is completely full."
In other words, the amount still in A at the end was
1231.5 - 904.8 = 326.7 ft^3
You are correct, I apologize for the mistake.
The amount of water remaining in Container A after pumping water into Container B is:
1231.5 - 904.8 = 326.7 cubic feet
Thank you for pointing that out.
First, we need to calculate the volume of water in each container.
The volume of a cylinder is given by the formula V = πr^2h, where r is the radius of the cylinder and h is the height.
For Container A:
Radius = diameter / 2 = 14 / 2 = 7 feet
Height = 8 feet
Volume of water in Container A = π(7)^2(8) ≈ 1231.5 cubic feet
For Container B:
Radius = diameter / 2 = 8 / 2 = 4 feet
Height = 17 feet
Volume of water in Container B = π(4)^2(17) ≈ 904.8 cubic feet
Since all of the water from Container A has been pumped into Container B, the remaining water volume in Container A is 0 cubic feet.
Therefore, the volume of water remaining in Container A, to the nearest tenth of a cubic foot, is 0 cubic feet.