Solve 2log base 3 x-3=4

To solve for x in the equation 2log base 3 x - 3 = 4, we first need to isolate the logarithm term:

2log base 3 x - 3 = 4
2log base 3 x = 4 + 3
2log base 3 x = 7

Next, we can divide both sides by 2 to isolate the logarithm:
log base 3 x = 7/2

Now, we can rewrite the equation in exponential form:
x = 3^(7/2)

Therefore, x = √(3^7) = √2187 = 47.58 (rounded to two decimal places).