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A box contains three red marbles and six blue marbles. What is the probability of selecting at random, without replacement, two blue marbles? (1 point)
Responses
1/9
1/12
5/12
4/9
First, find the total number of marbles in the box: 3 red + 6 blue = 9 marbles total.
Next, calculate the probability of selecting a blue marble on the first draw: 6 blue marbles / 9 total marbles = 2/3.
Since we are not replacing the marble, after selecting a blue marble on the first draw, there will be 8 marbles left in the box, with 5 blue marbles remaining.
Finally, calculate the probability of selecting a blue marble on the second draw: 5 blue marbles / 8 total marbles = 5/8.
Multiply the probabilities of the two events together to find the overall probability: 2/3 * 5/8 = 10/24 = 5/12.
Therefore, the probability of selecting at random, without replacement, two blue marbles is 5/12.
The correct answer is: 5/12