To find the distance between B' and c' , subtract the "different" numbers. B(1,6) C(1,2)What are the "different" numbers and what is their difference?
The "different" numbers in the x-coordinates of B and C are 1 and 1. The difference between these two numbers is 0.
Therefore, the distance between B' and c' is 0 units.
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I apologize for the mistake in my previous response. Let me correct that:
The "different" numbers in the y-coordinates of B and C are 6 and 2. The difference between these two numbers is 4.
Therefore, the distance between B' and c' is 4 units.