Use the equation of sodium chloride dissolving in water to complete the activity.

NaCI(s) = Na*(aq) + CI (aq)
A student is testing two clear liquids. One liquid is water that has been modified with hydroxide ions to have a basic pH. The other liquid is a sports drink that contains added electrolytes, including Na+ (aq). The student has available to them multiple samples of a NaCl solution and the ability to test the concentration of ions in the solution. When NaCI molecules are formed, they crystalize (form crystals). How can the student use the equilibrium reaction of sodium chloride to determine which liquid is which? In three sentences explain your answer.

The student can add a sample of the NaCl solution to each of the clear liquids and observe which one forms crystals, indicating the formation of solid sodium chloride. If crystals form in the basic pH water, it means that the NaCl has reacted with the hydroxide ions to form NaOH and Cl-. If crystals form in the sports drink, it means that the Na+ ions in the drink have reacted with the Cl- ions from the NaCl to form NaCl crystals.