Trend Lines Quick Check
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Question
Use the image to answer the question.
A scatterplot graph shows x-axis ranging from 0 to 50 and y-axis ranging from 0 to 10. Multiple points are plotted around a line that points downward to the right with an arrowhead on the bottom.
The x-axis is drawn in increments of 5 but labeled in increments of 10. The y-axis is drawn in increments of 1 but labeled in increments of 2. The line passes approximately through left parenthesis 0 comma 8 right parenthesis, left parenthesis 10 comma 6 right parenthesis, left parenthesis 15 comma 5 right parenthesis, left parenthesis 20 comma 4 right parenthesis, left parenthesis 25 comma three right parenthesis, and left parenthesis 40 comma 0 right parenthesis. 14 points are plotted close to or on the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
Responses
y=−15x+8
y equals negative Start Fraction 1 over 5 End Fraction x plus 8
y=5.67x+8
y equals 5.67 x plus 8
y=−15x+3
y equals negative Start Fraction 1 over 5 End Fraction x plus 3
y=15x+8
y equals Start Fraction 1 over 5 End Fraction x plus 8
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The correct answer is:
y = -0.2x + 8
nope wrong get right no
Apologies for the mistake. The correct equation in slope-intercept form of the trend line is:
y = -0.2x + 8
ok
If you have any more questions or need further clarification, feel free to ask. I'm here to help.
wrong
I apologize for the mistakes in my previous responses. Let's try solving the problem again.
Looking at the points provided in the scatterplot: (0,8), (10,6), (15,5), (20,4), (25,3), and (40,0), we can see a trend line that appears to have a slope of -0.2 and a y-intercept of 8.
Therefore, the correct equation in slope-intercept form of the trend line is:
y = -0.2x + 8
I hope this clears up any confusion. Thank you for your patience.
bro ur choosing the same answer
Let's reevaluate the points on the trend line to confirm the correct equation.
Points on the trend line: (0,8), (10,6), (15,5), (20,4), (25,3), and (40,0)
Calculating the slope using the points (0,8) and (40,0):
m = (0 - 8) / (40 - 0) = -8 / 40 = -0.2
Using the point-slope form with the point (0,8):
y - 8 = -0.2(x - 0)
y - 8 = -0.2x
y = -0.2x + 8
Therefore, the correct equation in slope-intercept form of the trend line is:
y = -0.2x + 8
Thank you for your patience, and I appreciate you pointing out the errors.