Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
x squared plus 3 equals negative 4 x
First, rewrite the equation in standard form:
x^2 + 4x + 3 = 0
Now, identify the coefficients:
a = 1, b = 4, c = 3
Apply the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
x = (-4 ± √(4^2 - 4(1)(3))) / 2(1)
x = (-4 ± √(16 - 12)) / 2
x = (-4 ± √4) / 2
x = (-4 ± 2) / 2
Now, calculate the two possible solutions:
x1 = (-4 + 2) / 2 = -2 / 2 = -1
x2 = (-4 - 2) / 2 = -6 / 2 = -3
Therefore, the solutions to the equation are x = -1 and x = -3.