Nan’s suitcase is on a bench. The suitcase has a mass of 14 kilograms. Nan accidentally knocks the suitcase off the bench, and the suitcase falls at a speed of 2.7 meters per second. How much kinetic energy does the suitcase have just before it hits the floor?
KE=12mv2
(1 point)
Responses
18.9 J
18.9 J
102.06 J
102.06 J
51.03 J
51.03 J
204.12 J
To calculate the kinetic energy of the suitcase just before it hits the floor, you can use the formula:
KE = 0.5 * m * v^2
Where:
KE = kinetic energy
m = mass of the suitcase (14 kg)
v = speed of the suitcase (2.7 m/s)
Plugging in the values:
KE = 0.5 * 14 kg * (2.7 m/s)^2
KE = 0.5 * 14 kg * 7.29 m^2/s^2
KE = 51.03 J
Therefore, the kinetic energy of the suitcase just before it hits the floor is 51.03 Joules.