2HCl(ag) + Zn(s) → ZnCl2(aq) + H2(g)
The molar mass of hydrogen (H) is 1g/mol, the molar mass of chlorine (Cl) is 35g/mol, and the molar mass of zinc (Zn) is 65g/mol. When 130g of zinc react completely in hydrochloric acid (HCl), how much is the total mass of the products?
(1 point)
Responses
130g
130g
274g
274g
270g
270g
144g
The balanced chemical equation shows that 1 mole of zinc produces 1 mole of hydrogen gas and 1 mole of zinc chloride.
First, calculate the number of moles of zinc in 130g:
130g / 65g/mol = 2 moles of Zn
Since the molar ratio of Zn to H2 is 1:1, there will be 2 moles of H2 produced.
Now, calculate the mass of H2 produced:
2 moles x 1 g/mol = 2g
The total mass of the products will be the mass of ZnCl2 + the mass of H2:
65g (ZnCl2) + 2g (H2) = 67g
Therefore, the total mass of the products is 67g.
The closest answer choice is 70g.
which out of these choices is correct
Apologies for the mistake in my previous response. Let's recalculate the total mass of the products:
Given:
130g of Zn reacts.
Calculate the molar mass of ZnCl2:
Zn = 65g/mol
Cl = 35g/mol x 2 = 70g/mol
Total molar mass of ZnCl2 = 65g/mol + 70g/mol = 135g/mol
Now, calculate the moles of Zn:
130g / 65g/mol = 2 moles of Zn
The reaction produces an equal number of moles of ZnCl2, so there will be 2 moles of ZnCl2.
Calculate the total mass of ZnCl2 produced:
2 moles x 135g/mol = 270g
Since the only gas produced is H2, the total mass of the products will be 270g (ZnCl2) + mass of H2.
Calculate the mass of H2 produced:
2 moles of Zn reacting produces 1 mole of H2.
1 mole of H2 has a molar mass of 2g.
2 moles x 2g/mol = 4g
Add the mass of H2 to the total mass of ZnCl2:
270g (ZnCl2) + 4g (H2) = 274g
Therefore, the correct answer is:
274g