A jar contains 10 red marbles, 6 blue marbles, 8 green marbles, and 4 yellow marbles. one marble is randomly drawn. What is the probability that either a yellow marble or a blue marble is drawn? (1 point) Responses 17 1 seventh 914 9 over 14 414 4 over 14 514
The probability of drawing either a yellow marble or a blue marble can be calculated by adding the individual probabilities of drawing a yellow marble and a blue marble.
Probability of drawing a yellow marble = Number of yellow marbles / total number of marbles
= 4 / (10 + 6 + 8 + 4)
= 4 / 28
= 1/7
Probability of drawing a blue marble = Number of blue marbles / total number of marbles
= 6 / 28
= 3 / 14
Therefore, the probability of drawing either a yellow marble or a blue marble is:
Probability = Probability of drawing a yellow marble + Probability of drawing a blue marble
= 1/7 + 3/14
= 2/14 + 3/14
= 5/14
So, the probability that either a yellow marble or a blue marble is drawn is 5/14.