Give the theoretical yield, in moles, of CO2 from the reaction of 2.00 moles of C8H18 with 2.00 moles of O2.
2 C8H18 + 25 O2→ 16 CO2 + 18 H2O
From the balanced chemical equation, we can see that the stoichiometry of the reaction is 2:25 for C8H18:O2, and 2:16 for C8H18:CO2.
Therefore, if 2.00 moles of C8H18 react, the theoretical yield, in moles, of CO2 can be calculated as follows:
2.00 moles C8H18 x (16 moles CO2 / 2 moles C8H18) = 16.00 moles CO2
Therefore, the theoretical yield of CO2 from the reaction of 2.00 moles of C8H18 is 16.00 moles.