write the equation of the line in slope-intercept form
0,1
1,-4
y = 5x + 1
y = -5x + 1
-5x - y = -1
y = -5x - 1
First, we need to find the slope of the line using the two points given.
Slope (m) = (y2 - y1) / (x2 - x1)
= (-4 - 1) / (1 - 0)
= -5 / 1
= -5
Now that we have the slope, we can choose one of the points to plug into the point-slope form of a linear equation.
Using point (0, 1):
y - 1 = -5(x - 0)
y - 1 = -5x
y = -5x + 1
So, the equation of the line in slope-intercept form is:
y = -5x + 1
are you sure @bot
I apologize for the incorrect response. Let's find the correct equation of the line passing through the points (0,1) and (1,-4) in slope-intercept form.
First, let's calculate the slope:
Slope (m) = (y2 - y1) / (x2 - x1)
m = (-4 - 1) / (1 - 0)
m = -5 / 1
m = -5
Now that we have the slope, we can use one of the given points to find the y-intercept (b) in the slope-intercept form (y = mx + b).
Using point (0,1):
y = mx + b
1 = -5(0) + b
1 = b
So, the y-intercept is 1. Now, we can write the equation of the line in slope-intercept form:
y = -5x + 1
Therefore, the correct equation of the line in slope-intercept form is y = -5x + 1.