Which set of events is dependent?(1 point)
Responses
choosing a marble from a box, replacing it, then choosing another marble
choosing a marble from a box, replacing it, then choosing another marble
choosing a ball from a bag and then choosing another ball without replacing the first
choosing a ball from a bag and then choosing another ball without replacing the first
rolling a number cube and flipping a coin
rolling a number cube and flipping a coin
the event of getting two heads when flipping two fair coins
A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana
Girls Boys Row total
Want the option to keep studying online 10 3 13
Don’t want the option to keep studying online 5 7 12
Column total 15 10 25
Which mathematical sentence can be used to calculate the probability of selecting a student who wants the option to keep studying online or is a boy?
(1 point)
Responses
1325+1025
Start Fraction 13 over 25 End Fraction plus Start Fraction 10 over 25 End Fraction
1325+1025−325
Start Fraction 13 over 25 End Fraction plus Start Fraction 10 over 25 End Fraction minus Start Fraction 3 over 25 End Fraction
325
Start Fraction 3 over 25 End Fraction
1325×1025
choosing a marble from a box, replacing it, then choosing another marble
The correct mathematical sentence that can be used to calculate the probability of selecting a student who wants the option to keep studying online or is a boy is:
Start Fraction 13 over 25 End Fraction plus Start Fraction 10 over 25 End Fraction
To calculate the probability of selecting an apple and a banana, we first need to find the total number of ways to select 2 fruits out of the total number of fruits.
Total number of fruits = 5 (bananas) + 8 (mangoes) + 7 (apples) = 20 fruits
Total number of ways to select 2 fruits out of 20 = C(20, 2) = 20! / (2! * (20-2)!) = 190 ways
Next, we calculate the number of ways to select 1 apple and 1 banana.
Number of ways to select 1 apple out of 7 = C(7, 1) = 7 ways
Number of ways to select 1 banana out of 5 = C(5, 1) = 5 ways
Number of ways to select 1 apple and 1 banana = 7 * 5 = 35 ways
Therefore, the probability of selecting an apple and a banana = Number of ways to select 1 apple and 1 banana / Total number of ways to select 2 fruits
= 35 / 190 = 7 / 38
So, the probability of selecting an apple and a banana is 7/38.