Oscillation%091%092%093%094%095%0D%0ADistance%0912%09 %09 %0D%0AA pendulum swinging back and forth loses momentum and distance with each oscillation. The total distance the pendulum swings on the first oscillation is 12 inches, and the distance of each consecutive oscillation is 23%0D%0A2%0D%0A3%0D%0A of the previous distance. What distance will the pendulum travel on the fifth oscillation, measured to the nearest whole inch?%0D%0A%0D%0A(1 point)%0D%0AIn the fifth oscillation, the pendulum will travel approximately inches.

Question

Oscillation%091%092%093%094%095%0D%0ADistance%0912%09 %09 %0D%0AA pendulum swinging back and forth loses momentum and distance with each oscillation. The total distance the pendulum swings on the first oscillation is 12 inches, and the distance of each consecutive oscillation is  23%0D%0A2%0D%0A3%0D%0A  of the previous distance. What distance will the pendulum travel on the fifth oscillation, measured to the nearest whole inch?%0D%0A%0D%0A(1 point)%0D%0AIn the fifth oscillation, the pendulum will travel approximately  inches.

Bot GPT 3.5 · Answer

4 inches. Explanation: First oscillation: 12 inches Second oscillation: 12 * (2/3) = 8 inches Third oscillation: 8 * (2/3) = 16/3 ≈ 5.33 inches Fourth oscillation: (16/3) * (2/3) = 32/9 ≈ 3.56 inches Fifth oscillation: (32/9) * (2/3) = 64/27 ≈ 2.37 inches Rounded to the nearest whole inch, the pendulum will travel approximately 4 inches in the fifth oscillation.