Oscillation%091%092%093%094%095%0D%0ADistance%0912%09 %09 %0D%0AA pendulum swinging back and forth loses momentum and distance with each oscillation. The total distance the pendulum swings on the first oscillation is 12 inches, and the distance of each consecutive oscillation is 23%0D%0A2%0D%0A3%0D%0A of the previous distance. What distance will the pendulum travel on the fifth oscillation, measured to the nearest whole inch?%0D%0A%0D%0A(1 point)
To find the distance the pendulum will travel on the fifth oscillation, we need to calculate the distance for each oscillation leading up to the fifth oscillation.
1st oscillation: 12 inches
2nd oscillation: 12 * 23% = 2.76 inches (rounded to 3 inches)
3rd oscillation: 3 * 23% = 0.69 inches (rounded to 1 inch)
4th oscillation: 1 * 23% = 0.23 inches (rounded to 0 inches)
Therefore, the distance the pendulum will travel on the fifth oscillation is 0 inches.