13. The area of a playground is 35 square yards. The width of the playground is 2 yd longer than its length. Find the length and width of the playground. (1 point)
Let the length of the playground be x yards.
Since the width of the playground is 2 yards longer than its length, the width can be represented as x + 2 yards.
Since the area of the playground is 35 square yards, we can set up the equation:
Length x Width = Area
x(x + 2) = 35
x^2 + 2x = 35
x^2 + 2x - 35 = 0
(x + 7)(x - 5) = 0
Solving for x, we get x = 5 or x = -7. Since the length cannot be negative, the length of the playground is 5 yards.
Plugging in the length into the equation for the width:
Width = 5 + 2 = 7 yards
Therefore, the length of the playground is 5 yards and the width is 7 yards.