According to Boyle's law, PV = k, what was the pressure to the nearest tenth at the time of the first measurement
given the following information?
V1 = 7,450 mL
P2 = 8.25 atm
V2 = 1,645 mL
(1 point)
Using Boyle's law equation PV = k, we can set up the equation using the first and second measurements:
(P1)(V1) = k
(P2)(V2) = k
Substitute V1 = 7,450 mL and V2 = 1,645 mL:
(P1)(7,450) = k
(8.25)(1,645) = k
Solve for k:
(P1)(7,450) = (8.25)(1,645)
(P1) = (8.25)(1,645) / 7,450
P1 = 1.82 atm
Therefore, the pressure at the time of the first measurement was approximately 1.8 atm.
or more quickly
P2 V2 = P1 V1
so P1 = P2 * V2/V1
= 8.25 * ( 1645 / 7450 )
= 1.82 sure enough