Triangle OPQ, with vertices O(8,4), P(7,8), and Q(4,7), is drawn on the coordinate grid below.What is the area, in square units, of triangle OPQ?What is the area, in square units, of triangle OPQ?
To calculate the area of triangle OPQ, we can use the formula for the area of a triangle given its coordinates:
Area = 1/2 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
Plugging in the coordinates for points O(8,4), P(7,8), and Q(4,7), we get:
Area = 0.5 * |8(8 - 7) + 7(7 - 4) + 4(4 - 8)|
Area = 0.5 * |8 + 7*3 + 4*(-4)|
Area = 0.5 * |8 + 21 - 16|
Area = 0.5 * |13|
Area = 0.5 * 13
Area = 6.5 square units
Therefore, the area of triangle OPQ is 6.5 square units.
THAT ISNT THE RIGHT ANSWER BOT
I apologize for the mistake. Let me recalculate the area of triangle OPQ with the correct formula.
Using the coordinates O(8,4), P(7,8), and Q(4,7), we can calculate the area using the following formula:
Area = 0.5 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
Plugging in the coordinates, we get:
Area = 0.5 * |8(8 - 7) + 7(7 - 4) + 4(4 - 8)|
Area = 0.5 * |8 + 7*3 + 4*(-4)|
Area = 0.5 * |8 + 21 - 16|
Area = 0.5 * |13|
Area = 0.5 * 13
Area = 6.5 square units
I apologize for my previous response. The correct answer is indeed 6.5 square units.
Triangle UVW, with vertices U(7,-8), V(9,-2), and W(3,-4), is drawn on the coordinate grid below.What is the area, in square units, of triangle UVW?
To calculate the area of triangle UVW, we can use the formula for the area of a triangle given its coordinates:
Area = 1/2 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
Plugging in the coordinates for points U(7,-8), V(9,-2), and W(3,-4), we get:
Area = 0.5 * |7(-2 -(-4)) + 9(-4 -(-8)) + 3(-8 -(-2))|
Area = 0.5 * |7(2) + 9(4) + 3(-6)|
Area = 0.5 * |14 + 36 - 18|
Area = 0.5 * 32
Area = 16 square units
Therefore, the area of triangle UVW is 16 square units.
What is the area, in square feet, of the trapezoid, 17.5,7.6,9.6
In order to calculate the area of a trapezoid, we need to have the lengths of both parallel sides and the height of the trapezoid.
Given the lengths of the parallel sides as 17.5 ft and 9.6 ft, and also the height as 7.6 ft, we can use the formula for the area of a trapezoid:
Area = 0.5 * (a + b) * h
where
a = length of the first parallel side = 17.5 ft
b = length of the second parallel side = 9.6 ft
h = height of the trapezoid = 7.6 ft
Plugging in these values into the formula:
Area = 0.5 * (17.5 + 9.6) * 7.6
Area = 0.5 * 27.1 * 7.6
Area = 0.5 * 205.96
Area = 102.98 square feet
Therefore, the area of the trapezoid is 102.98 square feet.
THAT ISNT THE RIGHT ANSWER
I apologize for the error. Let's recalculate the area of the trapezoid with the given dimensions 17.5 ft, 7.6 ft, and 9.6 ft.
To find the area of a trapezoid, you can use the formula:
Area = 0.5 * (a + b) * h
where a and b are the lengths of the parallel sides, and h is the height of the trapezoid.
Plugging in the values:
a = 17.5 ft
b = 9.6 ft
h = 7.6 ft
Area = 0.5 * (17.5 + 9.6) * 7.6
Area = 0.5 * 27.1 * 7.6
Area = 0.5 * 205.96
Area = 102.98 square feet
Therefore, the area of the trapezoid with lengths 17.5 ft, 7.6 ft, and 9.6 ft is 102.98 square feet.