What is the surface area of a rectangular prism whose dimensions are 334 dm×412 dm×5 dm in square decimeters?
1. 84 3/8 dm^2
2. 58 1/8 8 dm^2
3. 116 1/4 dm^2
4. 16 dm^2
The surface area of a rectangular prism can be calculated using the formula: 2lw + 2lh + 2wh, where l is length, w is width, and h is height.
Plugging in the given dimensions:
l = 334 dm
w = 412 dm
h = 5 dm
Surface area = 2(334)(412) + 2(334)(5) + 2(412)(5)
Surface area = 274856 dm^2 + 3340 dm^2 + 2060 dm^2
Surface area = 280256 dm^2
Therefore, the surface area of the rectangular prism is 280256 square decimeters.
None of the provided options match the correct answer.