A sample of He gas (2.35 mol) occupies 57.9 L at 300.0 K and 1.00 atm. The volume of this sample is ________ L at 521 K and 1.00 atm.
To find the final volume of the sample at 521 K and 1.00 atm, we need to use the combined gas law formula:
(P₁V₁) / (T₁) = (P₂V₂) / (T₂)
Where:
P₁ = initial pressure (1.00 atm)
V₁ = initial volume (57.9 L)
T₁ = initial temperature (300.0 K)
P₂ = final pressure (1.00 atm)
V₂ = final volume (unknown)
T₂ = final temperature (521 K)
Plug in the values:
(1.00 atm * 57.9 L) / (300.0 K) = (1.00 atm * V₂) / (521 K)
Solve for V₂:
V₂ = (1.00 atm * 57.9 L * 521 K) / (300.0 K)
V₂ = 100.67 L
Therefore, the final volume of the sample at 521 K and 1.00 atm is approximately 100.67 L.