A closed-end manometer was attached to a vessel containing argon. The difference in the mercury levels in the two arms of the manometer was 10.1 cm. Atmospheric pressure was 783 mm Hg. The pressure of the argon in the container was ________ mm Hg.
The pressure of the argon in the container can be calculated using the formula:
Pressure of gas in container = Atmospheric pressure + Difference in mercury levels
Pressure of gas in container = 783 mm Hg + 10.1 cm = 783 mm Hg + 10.1 mm Hg
Pressure of gas in container = 793.1 mm Hg
Therefore, the pressure of the argon in the container was 793.1 mm Hg.