The dimensions of rectangle B are twice the dimensions of rectangle A. The area of rectangle A is 50 cm2.
What is the area of rectangle B?
Since the dimensions of rectangle B are twice the dimensions of rectangle A, if the area of rectangle A is 50 cm2, then the dimensions of rectangle B must be twice the dimensions of rectangle A.
Let the dimensions of rectangle A be length = x cm and width = y cm. Therefore, the area of rectangle A = x * y = 50 cm2.
The dimensions of rectangle B would then be length = 2x cm and width = 2y cm. Therefore, the area of rectangle B = 2x * 2y = 4xy.
Since the area of rectangle A is 50 cm2, we have x * y = 50. Therefore, 4xy = 4 * 50 = 200 cm2.
So, the area of rectangle B is 200 cm2.