The dimensions of triangle B are twice the dimensions of triangle A. The area of triangle B is 112 cm2.
What is the area of triangle A?
Let's denote the base and height of triangle A as b and h, respectively.
Since the dimensions of triangle B are twice that of triangle A, we can express the base and height of triangle B in terms of b and h as 2b and 2h.
The formula for the area of a triangle is A = 1/2 * base * height.
Therefore, the area of triangle B is:
112 = 1/2 * 2b * 2h
112 = 2b * h
Now, we want to find the area of triangle A:
A = 1/2 * b * h
Since the dimensions of triangle B are twice the dimensions of triangle A, we can express b and h as b = 1/2 * 2b and h = 1/2 * 2h.
Substitute these expressions into the formula for the area of triangle A:
A = 1/2 * 1/2 * 2b * 1/2 * 2h
A = 1/4 * 4bh
A = bh
From the equation we derived for triangle B, we know that bh = 56.
Therefore, the area of triangle A is 56 cm^2.