Use the image to answer the question. An illustration of a scatterplot shows x on x-axis from 65 to 75 in increments of 1 and y on the y-axis from 200 to 240 in increments of 2.5. Eleven points are plotted. The approximate plotted points are as follows: left parenthesis 65 comma 205 right parenthesis, left parenthesis 67 comma 216 right parenthesis, left parenthesis 68 comma 210 right parenthesis, left parenthesis 68 comma 218 right parenthesis, left parenthesis 69 comma 224 right parenthesis, left parenthesis 70 comma 220 right parenthesis, left parenthesis 70 comma 224 right parenthesis, left parenthesis 71 comma 230 right parenthesis, left parenthesis 72 comma 235 right parenthesis, left parenthesis 74 comma 200 right parenthesis, and left parenthesis 74 comma 240 right parenthesis. Is there a relationship between the two sets of data? How do you know?
Based on the scatterplot and the plotted points, it appears that there is a positive relationship between the two sets of data. As the x-values increase, the y-values also tend to increase. This can be observed by the general trend of the points moving upwards from left to right on the scatterplot. Additionally, if a line of best fit were to be drawn through the points, it would have a positive slope. Therefore, there is a relationship between the two sets of data, and it seems to be a positive correlation.
s, because the data points are not close to the trend line.Yes, because the data points are not close to the trend line.No, because the data points are not close to the trend line.No, because the data points are not close to the trend line.Yes, because the data points are close to the trend line.Yes, because the data points are close to the trend line.No, because the data points are close to the trend line.
No, because the data points are not close to the trend line.
Use the image to answer the question.An illustration of a scatterplot shows x on x-axis from 65 to 75 in increments of 1 and y on the y-axis from 200 to 240 in increments of 2.5. Eleven points are plotted. The approximate plotted points are as follows: left parenthesis 65 comma 205 right parenthesis, left parenthesis 67 comma 216 right parenthesis, left parenthesis 68 comma 210 right parenthesis, left parenthesis 68 comma 218 right parenthesis, left parenthesis 69 comma 224 right parenthesis, left parenthesis 70 comma 220 right parenthesis, left parenthesis 70 comma 224 right parenthesis, left parenthesis 71 comma 230 right parenthesis, left parenthesis 72 comma 235 right parenthesis, left parenthesis 74 comma 200 right parenthesis, and left parenthesis 74 comma 240 right parenthesis. Are there any outliers in the data shown on the scatterplot? If so, where?(1 point)ResponsesNo, there are no outliers in the data.No, there are no outliers in the data.Yes, at (74, 240)Yes, at left parenthesis 74 comma 240 right parenthesisYes, at (65, 205)Yes, at left parenthesis 65 comma 205 right parenthesisYes, at (74, 200)
No, there are no outliers in the data.
Use the image to answer the question.An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 10 in increments of 1. Multiple points are plotted around a line that points downward to the right with an arrowhead on the bottom.The line passes approximately through left parenthesis 0 comma 9 right parenthesis, left parenthesis 4 comma 8 right parenthesis, left parenthesis 8 comma 7 right parenthesis, and left parenthesis 10 comma 6.5 right parenthesis. 12 points are plotted close to the line.Write an equation in slope-intercept form of the trend line.(1 point)Responsesy=−14x+9y equals negative Start Fraction 1 over 4 End Fraction x plus 9y=1x+9y equals 1 x plus 9y=−58x+9y equals negative Start Fraction 5 over 8 End Fraction x plus 9y=−14x
To write the equation in slope-intercept form of the trend line, we need to find the slope and y-intercept using two points on the line. Let's use the points (0, 9) and (10, 6.5).
First, calculate the slope:
slope (m) = (y2 - y1) / (x2 - x1)
m = (6.5 - 9) / (10 - 0) = -2.5 / 10 = -0.25
Now, we can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
Using the point (0, 9):
y - 9 = -0.25(x - 0)
y - 9 = -0.25x
y = -0.25x + 9
Therefore, the equation in slope-intercept form of the trend line is:
y = -0.25x + 9