6. How many moles of CaO are needed to react with excess water to produce 370 g of calcium bydroxide?
The balanced chemical equation for the reaction between CaO and water to produce calcium hydroxide is:
CaO + H2O -> Ca(OH)2
From the equation, we can see that one mole of CaO will produce one mole of Ca(OH)2.
The molar mass of CaO is 56.08 g/mol, and the molar mass of Ca(OH)2 is 74.09 g/mol.
First, we need to calculate the number of moles of Ca(OH)2 produced from 370 g of Ca(OH)2:
Number of moles = mass / molar mass
Number of moles = 370 g / 74.09 g/mol
Number of moles = 5 moles
Since one mole of CaO produces one mole of Ca(OH)2, we need 5 moles of CaO to react with water to produce 370 g of calcium hydroxide.