A team of students collected data on the growth of a plant. They plotted the height of the plant every day and found the line of best fit y=0.23x+9.9%0D%0A%0D%0A=%0D%0A0.23%0D%0A%0D%0A+%0D%0A9.9%0D%0A for the growth of the plant. If the actual data point for day six is (6,7.82)%0D%0A(%0D%0A6%0D%0A,%0D%0A7.82%0D%0A)%0D%0A , what is the residual of the data point for day six? Round the answer to the nearest hundredths.(1 point)%0D%0AThe residual of the data point (6,7.82)%0D%0A(%0D%0A6%0D%0A,%0D%0A7.82%0D%0A)%0D%0A is .

The residual can be calculated by finding the difference between the actual value and the predicted value (based on the line of best fit).

Predicted value for day six:
y = 0.23(6) + 9.9
y = 1.38 + 9.9
y = 11.28

Residual:
Residual = Actual value - Predicted value
Residual = 7.82 - 11.28
Residual = -3.46

Therefore, the residual of the data point (6,7.82) is -3.46.