Draw the molecular obital diagram for N2^+2
To draw the molecular orbital diagram for N2+2, we first need to determine the number of valence electrons in the molecule. N2+2 has 15 valence electrons (7 from each nitrogen atom plus the +2 charge).
The molecular orbital diagram for N2+2 would have the following configuration:
1. The 1s orbitals overlap to form a σ1s bonding and a σ1s* antibonding molecular orbital.
2. The 2s orbitals overlap to form a σ2s bonding and a σ2s* antibonding molecular orbital.
3. The three 2p orbitals on each nitrogen atom overlap to form σ2p, π2p and π2p* bonding and antibonding molecular orbitals.
The diagram would look like:
1. σ2p* (4 electrons)
2. σ2p* (4 electrons)
3. π2p* (2 electrons)
4. π2p (2 electrons)
5. σ2p (2 electrons)
6. σ2s* (2 electrons)
7. σ2s (2 electrons)
8. σ1s* (2 electrons)
9. σ1s (2 electrons)
Overall, after filling in the electrons based on their respective molecular orbitals, there will be 15 valence electrons present in the N2+2 molecule.