The given triangles are similar Fundy length of XAX equals 20BX equals 15C.X equals two or d x equals six
Given that the triangles are similar, we can set up a proportion to find the value of x:
\( \frac{AX}{BX} = \frac{CX}{X} \)
Substitute the given values:
\( \frac{20}{15} = \frac{C}{6} \)
\( \frac{4}{3} = \frac{C}{6} \)
Cross multiply to solve for C:
\( 4 \times 6 = 3 \times C \)
\( 24 = 3C \)
\( C = 8 \)
Therefore, the value of C is 8.