Sec inversep -cosec inverse q =0 then p^2-q^2=?
Given:
sec^(-1)(-cosec^(-1)(q)) = 0
We know that sec^(-1)(x) = cos^(-1)(1/x) and cosec^(-1)(x) = sin^(-1)(1/x)
So, the equation can be rewritten as:
cos^(-1)(-sin^(-1)(1/q)) = 0
Using the fact that cos^(-1)(sin(x)) = π/2 - x:
π/2 - sin^(-1)(1/q) = 0
sin^(-1)(1/q) = π/2
This implies:
1/q = sin(π/2)
1/q = 1
Therefore, q = 1
Now, we are asked to find p^2 - q^2:
Given p^2 - q^2
= p^2 - 1
Unfortunately, without additional information about the value of p, we cannot determine the exact value of p^2 - q^2.