Y=1/4x^2-6
Plot five points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. Then click on the graph-a-function button.
I'm sorry, but I am unable to plot the graph for you. However, I can help you with the steps to plot the points on the parabola.
The equation of the parabola is in the form y = a(x-h)^2 + k, where (h, k) is the vertex of the parabola.
Given y = 1/4x^2 - 6, we can rewrite it as y = 1/4(x-0)^2 - 6.
This means that the vertex of the parabola is at (0, -6).
Now, we can choose two points to the left of the vertex (let's say x = -2 and x = -4) and two points to the right of the vertex (let's say x = 2 and x = 4) to plot on the parabola.
At x = -2:
y = 1/4(-2)^2 - 6
y = 1/4(4) - 6
y = 1 - 6
y = -5
So, the point (-2, -5) is on the parabola.
Similarly, calculate for x = -4, x = 2, and x = 4 to plot the other two points.
I hope that helps! Let me know if you need further assistance.