Calculate the frequency of photon emitted when a transition take place from a higher energy level of -0.85eV to lower energy level at -13.60 eV
To calculate the frequency of the photon emitted during this transition, we can use the formula:
E = hf
where:
E = energy difference between the two energy levels
h = Planck's constant (6.626 x 10^-34 J·s)
First, we need to calculate the energy difference between the two energy levels:
E = -13.60 eV - (-0.85 eV)
E = -12.75 eV
Now convert this energy difference to joules:
1 eV = 1.602 x 10^-19 J
-12.75 eV = -12.75 x 1.602 x 10^-19 J
-12.75 eV = -2.0445 x 10^-18 J
Now, we can plug this energy difference into the formula to calculate the frequency of the photon:
E = hf
-2.0445 x 10^-18 J = h x f
Rearranging the formula to solve for frequency:
f = E / h
f = (-2.0445 x 10^-18 J) / (6.626 x 10^-34 J·s)
f ≈ 3.08 x 10^15 Hz
Therefore, the frequency of the photon emitted during this transition is approximately 3.08 x 10^15 Hz.