Assume that a sample is used to estimate a population mean μ. Use the given confidence level and sample data to find the margin of error. Assume that the sample is a simple random sample and the population has a normal distribution. Round your answer to one more decimal place than the sample standard deviation. 95% confidence; n=91; /x=16, s=9.1
A. 4.10
B. 1.90
C. 1.71
D. 1.63
Margin of error = Critical value * (Standard deviation / sqrt(n))
First, we need to find the critical value for a 95% confidence level with a sample size of 91. The critical value can be found using a t-distribution table or calculator. For a 95% confidence level and 90 degrees of freedom (n-1), the critical value is approximately 1.664.
Now, we can calculate the margin of error:
Margin of error = 1.664 * (9.1 / sqrt(91))
Margin of error ≈ 1.71
Therefore, the correct answer is:
C. 1.71