Consider the first four terms in this geometric sequence:
-6, 18, -54, 162
If T_n is the nth term, evaluate \frac{T_2}{T_1}
\frac{T_2}{T_1} = ?
To find the value of \frac{T_2}{T_1}, we first need to identify the values of T_1 and T_2 in the given sequence:
T_1 = -6
T_2 = 18
Now, we can substitute these values into the formula \frac{T_2}{T_1}:
\frac{T_2}{T_1} = \frac{18}{-6} = -3
Therefore, \frac{T_2}{T_1} = -3.
evaluate \frac{T_3}{T_2}
To find the value of \frac{T_3}{T_2}, we need to identify the values of T_2 and T_3 in the given sequence:
T2 = 18
T3 = -54
Now, we can substitute these values into the formula \frac{T_3}{T_2}:
\frac{T_3}{T_2} = \frac{-54}{18} = -3
Therefore, \frac{T_3}{T_2} = -3.