What should the mole percent of oxygen be in the diving gas for the partial pressure of oxygen in the mixture to be 0.21 atm
, the same as in air at 1 atm
?
The mole percent of oxygen in the diving gas can be calculated using the partial pressure of oxygen in the mixture, which is 0.21 atm, and the total pressure of the mixture, which is 1 atm:
Mole fraction of oxygen = Partial pressure of oxygen / Total pressure of mixture
Mole fraction of oxygen = 0.21 atm / 1 atm
Mole fraction of oxygen = 0.21
To convert the mole fraction to mole percent, we multiply by 100:
Mole percent of oxygen = 0.21 x 100 = 21%
Therefore, the mole percent of oxygen in the diving gas should be 21% in order for the partial pressure of oxygen in the mixture to be 0.21 atm, the same as in air at 1 atm.