A fixed quantity of gas at 23 ∘C
exhibits a pressure of 759 torr
and occupies a volume of 5.52 L
.Calculate the volume the gas will occupy if the pressure is increased to 1.89 atm
while the temperature is held constant.
First, let's convert the initial pressure from torr to atm:
1 atm = 760 torr
Initial pressure = 759 torr / 760 torr/atm = 0.9987 atm
Now, we can use the combined gas law equation:
P1V1 = P2V2
Where:
P1 = initial pressure = 0.9987 atm
V1 = initial volume = 5.52 L
P2 = final pressure = 1.89 atm
V2 = final volume (unknown)
Plugging in the values:
0.9987 atm * 5.52 L = 1.89 atm * V2
5.5116 = 1.89 * V2
V2 = 5.5116 / 1.89
V2 = 2.9145 L
Therefore, the gas will occupy a volume of 2.9145 L when the pressure is increased to 1.89 atm and the temperature is held constant.