A sample of neon gas has a volume of 2.85 L and a temperature of 15 °C, under a constant pressure. What is the new temperature (in °C), if the volume is decreased to 1.45 L?
To calculate the new temperature, we can use the formula:
V1/T1 = V2/T2
Where:
V1 = initial volume = 2.85 L
T1 = initial temperature = 15 °C
V2 = final volume = 1.45 L
T2 = final temperature (to be calculated)
Plugging in the values:
2.85/15 = 1.45/T2
Solving for T2:
T2 = (1.45 * 15) / 2.85
T2 = 7.63 °C
Therefore, the new temperature is 7.63 °C.