a 10.0-mL sample of HCl requires 32.34 mL of 0.108 M NaOH to reach the endpoint. what is the molar concentration of HCl? the equation for the reaction is
HCl + NaOH -> NaCl + H2O
First, we need to determine the moles of NaOH used in the reaction:
moles of NaOH = volume of NaOH (L) * molarity of NaOH (mol/L)
moles of NaOH = 32.34 mL * 0.108 mol/L = 3.49152 x 10^-3 mol
Since the reaction is 1:1 between HCl and NaOH, the moles of HCl is equal to the moles of NaOH used. Now, we can calculate the molarity of HCl:
molarity of HCl = moles of HCl / volume of HCl (L)
molarity of HCl = 3.49152 x 10^-3 mol / 10.0 mL = 0.349152 mol/L = 0.349 M
Therefore, the molar concentration of HCl is 0.349 M.