Find the area of the figure below.
COURSE TOOLS
7 in
6 in:
A = = (61+b2) (h) (2 points)
12 in
item 4
tem2
Item 3
Item 4
Item 5
Item 6
Item 7
O a. 114 in?
06. 57 in?
O c. 25 in?
O d. 12.5 in?
To find the area of the figure, we need to find the area of the triangle and the rectangle separately and then add them together.
Area of triangle = 1/2 * base * height
Area of triangle = 1/2 * 6 * 7
Area of triangle = 21 sq in
Area of rectangle = length * width
Area of rectangle = 12 * 7
Area of rectangle = 84 sq in
Total area = Area of triangle + Area of rectangle
Total area = 21 + 84
Total area = 105 sq in
Therefore, the correct answer is not among the options given. The area of the figure is 105 sq in.
u sure?
Apologies for the mistake in my previous response. Let's re-calculate the area of the figure correctly.
Given:
Length of rectangle = 12 in
Width of rectangle = 7 in
Base of triangle = 6 in
Height of triangle = 7 in
Area of rectangle = length * width
Area of rectangle = 12 * 7
Area of rectangle = 84 sq in
Area of triangle = 1/2 * base * height
Area of triangle = 1/2 * 6 * 7
Area of triangle = 21 sq in
Total area = Area of rectangle + Area of triangle
Total area = 84 + 21
Total area = 105 sq in
Therefore, the correct area of the figure is indeed 105 sq in. The correct answer is not among the options given.
but thats not an option
I apologize for the mistake in the options. Let's double-check the calculation:
Area of triangle = 1/2 * base * height
Area of triangle = 1/2 * 6 * 7
Area of triangle = 21 sq in
Area of rectangle = length * width
Area of rectangle = 12 * 7
Area of rectangle = 84 sq in
Total area = Area of triangle + Area of rectangle
Total area = 21 + 84
Total area = 105 sq in
Since 105 sq in is not listed among the options, let's re-calculate the area with the given dimensions to ensure accuracy.
Total area = (base x height / 2) + (length x width)
Total area = (6 x 7 / 2) + (12 x 7)
Total area = (42 / 2) + 84
Total area = 21 + 84
Total area = 105 sq in
The correct area of the figure is indeed 105 sq in. If this option is not listed, it appears there may be an error in the provided answer choices.