A toy came in a container that is shaped like a triangular prism. How much wrapping paper is needed to wrap the toy? Round your answer to the nearest whole number.
(1 point)
S.A. =
cm2
the langhts are
28.4cm
27.9cm
30.5cm
5.1cm
/.
To find the surface area of the triangular prism, we need to find the area of each of the three rectangular faces and then add them together.
Face 1: 28.4 cm x 27.9 cm = 792.36 cm²
Face 2: 28.4 cm x 30.5 cm = 866.2 cm²
Face 3: 27.9 cm x 30.5 cm = 850.95 cm²
Total surface area = 792.36 cm² + 866.2 cm² + 850.95 cm² = 2509.51 cm²
Rounded to the nearest whole number, the amount of wrapping paper needed to wrap the toy is 2510 cm².