Calculate the change in heat for the reaction 2C + H2 > C2H2 given the following chemical equations and their respective enthalpy changes
i) C2H2 + 5/2Og >>>>>2CO2 + H2O
ii) 2C + 2O2 >>>>> 2CO2
iii) H2 + 1/2 O2 >>>>>>>>> H2O enthalpy change = -285.8kg/mol
To find the change in heat for the reaction 2C + H2 > C2H2, we need to sum up the enthalpy changes of the given chemical equations.
i) C2H2 + 5/2O2 >>>>> 2CO2 + H2O (enthalpy change = -1300.8 kJ/mol)
ii) 2C + 2O2 >>>>> 2CO2 (enthalpy change = -566 kJ/mol)
iii) H2 + 1/2 O2 >>>>>>>>> H2O (enthalpy change = -285.8 kJ/mol)
First, we need to balance the given reaction:
2C + H2 > C2H2
Now, summing up the enthalpy changes of the reactions:
-1300.8 kJ/mol + (-285.8 kJ/mol)
= -1586.6 kJ/mol
Therefore, the change in heat for the reaction 2C + H2 > C2H2 is -1586.6 kJ/mol.