A current of 4.00 A flows in a conductor for 6.00 s. How many electrons pass a given point in the conductor during this time?
To find the number of electrons passing a given point in the conductor, we can use the formula:
Q = It
where Q is the charge in coulombs, I is the current in amperes, and t is the time in seconds.
Given that the current is 4.00 A and it flows for 6.00 s, we have:
Q = 4.00 A x 6.00 s = 24.00 C
Now, we know that 1 coulomb is equal to approximately 6.242 x 10^18 electrons.
So, the number of electrons passing a given point in the conductor during this time is:
24.00 C x 6.242 x 10^18 electrons/C ≈ 149.81 x 10^18 electrons
Therefore, approximately 1.50 x 10^20 electrons pass a given point in the conductor during this time.