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An illustration shows a triangular pyramid with an equilateral base. The perpendicular height of the base measures 12 inches and all sides measure 14 inches. The slant height measures 13 inches.
Use nets to find the surface area of the triangular pyramid with an equilateral base.
(1 point)
Responses
273 in.2
273 in. squared
84 in.2
84 in. squared
357 in.2
357 in. squared
175 in.2
175 in. squared
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Use the image to answer the question.
An illustration shows a net diagram of a tetrahedron. The net diagram is in the shape of a parallelogram. The net diagram is formed by connecting 4 identical triangles horizontally. From left to right, the first and third triangles rest on their bases. The second and fourth triangles are inverted. The side edges where each triangle meets the next are marked by dashed lines.
The tetrahedron has a surface area of 20 m2. What is the area of one face of the tetrahedron?
(1 point)
Responses
10 m2
10 m squared
15 m2
15 m squared
20 m2
20 m squared
5 m2
Use the image to answer the question.
An illustration shows a net diagram of a tetrahedron. The net diagram is in the shape of a parallelogram. The net diagram is formed by connecting 4 identical triangles horizontally. From left to right, the first and third triangles rest on their bases. The second and fourth triangles are inverted. The side edges where each triangle meets the next are marked by dashed lines. The base length of the first triangle measures 8 inches. The slant height is indicated by a perpendicular line on the first triangle and measures 7 inches.
What is the surface area of the tetrahedron?
(1 point)
Responses
112 in.2
112 in. squared
224 in.2
224 in. squared
28 in.2
28 in. squared
84 in.2
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An illustration shows a 3 D trianglular pyramid. The edges that are not visible are represented by dashed lines. The base measurements are 3 inches, 3 inches, and 5.2 inches. The perpendicular height of the base, drawn with a dotted line, is labeled as h equals 1.5 inches. The triangular face edges are labeled as h equals 6 inches 6 inches. A dotted line bisects the right visible face from the apex to the center of the base and is labeled as s h equals 5.81 inches.
Which net could be used to find the surface area of the paperweight diagrammed above?
(1 point)
Responses
An illustration shows the net of a triangular pyramid. An inverted central isosceles triangle has three isosceles triangles extending from each side. The top side of the inverted central triangle is labeled as 5.2 inches. The left side is labeled as 3 inches. A vertical dashed line bisects the central inverted triangle from base to apex and is labeled as h equals 1.5 inches. The top triangle extending from the central triangle is labeled 6 inches on its right side. The base, which is also the top of the central triangle, is labeled 5.2 inches. The triangle extending from the lower 3-inch left side of the central triangle is bisected by a dashed line from apex to base labeled as h equals 5.81 inches. The triangle extending from the right side of the central triangle is identical to the one extending from the left side of the central triangle, without the dashed bisecting line.
Image with alt text: An illustration shows the net of a triangular pyramid. An inverted central isosceles triangle has three isosceles triangles extending from each side. The top side of the inverted central triangle is labeled as 5.2 inches. The left side is labeled as 3 inches. A vertical dashed line bisects the central inverted triangle from base to apex and is labeled as h equals 1.5 inches. The top triangle extending from the central triangle is labeled 6 inches on its right side. The base, which is also the top of the central triangle, is labeled 5.2 inches. The triangle extending from the lower 3-inch left side of the central triangle is bisected by a dashed line from apex to base labeled as h equals 5.81 inches. The triangle extending from the right side of the central triangle is identical to the one extending from the left side of the central triangle, without the dashed bisecting line.
An illustration shows the net of a triangular pyramid. An inverted central isosceles triangle has three isosceles triangles extending from its sides. The top base of the inverted central triangle is labeled as 3 inches. The left and right sides are labeled as 5.2 inches. A vertical dashed line bisects the central triangle and is labeled as h equals 1.5 inches. The top triangle extending from the central triangle is labeled as 6 inches on its right side. The base, which is also the top of the central triangle, is labeled as 3 inches. The triangle extending from the lower left 5.2-inch side of the central triangle has a dotted line bisecting its length, representing the slant height, that is labeled as h equals 5.81 inches. The triangle extending from the right side of the central triangle is identical to the one extending from the left side of the central triangle, without the dashed bisecting line.
Image with alt text: An illustration shows the net of a triangular pyramid. An inverted central isosceles triangle has three isosceles triangles extending from its sides. The top base of the inverted central triangle is labeled as 3 inches. The left and right sides are labeled as 5.2 inches. A vertical dashed line bisects the central triangle and is labeled as h equals 1.5 inches. The top triangle extending from the central triangle is labeled as 6 inches on its right side. The base, which is also the top of the central triangle, is labeled as 3 inches. The triangle extending from the lower left 5.2-inch side of the central triangle has a dotted line bisecting its length, representing the slant height, that is labeled as h equals 5.81 inches. The triangle extending from the right side of the central triangle is identical to the one extending from the left side of the central triangle, without the dashed bisecting line.
An illustration shows the net of a triangular pyramid. An inverted central isosceles triangle has three isosceles triangles extending from each side. The top side of the inverted central triangle is labeled as 5.2 inches. The left side is labeled as 3 inches. A vertical dashed line bisects the central inverted triangle from base to apex and is labeled as h equals 5.81 inches. The top triangle extending from the central triangle is labeled 6 inches on its right side. The base, which is also the top of the central triangle, is labeled 5.2 inches. The triangle extending from the lower 3-inch left side of the central triangle is bisected by a dashed line from apex to base labeled as h equals 1.5 inches. The triangle extending from the right side of the central triangle is identical to the one extending from the left side of the central triangle, without the dashed bisecting line.
Image with alt text: An illustration shows the net of a triangular pyramid. An inverted central isosceles triangle has three isosceles triangles extending from each side. The top side of the inverted central triangle is labeled as 5.2 inches. The left side is labeled as 3 inches. A vertical dashed line bisects the central inverted triangle from base to apex and is labeled as h equals 5.81 inches. The top triangle extending from the central triangle is labeled 6 inches on its right side. The base, which is also the top of the central triangle, is labeled 5.2 inches. The triangle extending from the lower 3-inch left side of the central triangle is bisected by a dashed line from apex to base labeled as h equals 1.5 inches. The triangle extending from the right side of the central triangle is identical to the one extending from the left side of the central triangle, without the dashed bisecting line.
An illustration of a net shows two large identical isosceles triangles joined by a common base and arranged vertically. Two smaller isosceles triangles are joined to the left and right sides of the bottom inverted isosceles triangle. The common base of the two joined isosceles mirror-image triangles is 5.2 inches, and the left and right sides are labeled as 6 inches. A vertical dotted line bisects the top triangle from apex to base and is labeled as h equals 5.81 inches. The length of the each of the joined edges of the smaller triangles sharing the outer edges of the larger inverted bottom triangle is labeled 6 as inches. The outer edges are also labeled as 6 inches. The bases of the two side triangles are labeled as 3 inches.
Image with alt text: An illustration of a net shows two large identical isosceles triangles joined by a common base and arranged vertically. Two smaller isosceles triangles are joined to the left and right sides of the bottom inverted isosceles triangle. The common base of the two joined isosceles mirror-image triangles is 5.2 inches, and the left and right sides are labeled as 6 inches. A vertical dotted line bisects the top triangle from apex to base and is labeled as h equals 5.81 inches. The length of the each of the joined edges of the smaller triangles sharing the outer edges of the larger inverted bottom triangle is labeled 6 as inches. The outer edges are also labeled as 6 inches. The bases of the two side triangles are labeled as 3 inches.
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Use the image to answer the question.
An illustration shows a triangular pyramid made with rows of chocolate covered candies. The base measures 16 inches, the side of the triangular face measures 16 inches, and the vertical height is 13.86 inches.
Compute the surface area of the chocolate tower.
(1 point)
Responses
443.52 in.2
443.52 in. squared
554.4 in.2
554.4 in. squared
1,884.96 in.2
1,884.96 in. squared
460.64 in.2
The correct response is:
443.52 in.2