What are the forces (in N) on two charges of +0.200 C and −4.00 C, respectively, if they are separated by a distance of 4.00 m?
The force between two charges can be calculated using Coulomb's law, which states:
F = k * |q1 * q2| / r^2
where:
F is the force between the charges,
k is Coulomb's constant (8.99 x 10^9 N m^2/C^2),
q1 is the magnitude of the first charge,
q2 is the magnitude of the second charge,
r is the distance between the charges.
For the two charges of +0.200 C and -4.00 C separated by a distance of 4.00 m, the force between them can be calculated as:
F = (8.99 x 10^9 N m^2/C^2) * |0.200 C * -4.00 C| / (4.00 m)^2
F = (8.99 x 10^9) * |0.200 * 4.00| / (4.00)^2
F = (8.99 x 10^9) * 0.8 / 16
F = 44.9375 x 10^7 N
F = 4.49 x 10^8 N
Therefore, the force between the +0.200 C and -4.00 C charges separated by 4.00 m is 4.49 x 10^8 N.