the atomic mass of the element platinum (Pt) is 195.08 amu. How many atoms of platinum are in 195.08 grams?
A. 3.087 x 10^21 atoms
B. 6.022 x 10^23 atoms
C. 1.175 x 10^26 atoms
D. 1.951 x 10^25 atoms
To determine how many atoms of platinum are in 195.08 grams, we first need to convert grams to moles using the molar mass of platinum.
1 mole of platinum = 195.08 grams
1 mole of platinum = 6.022 x 10^23 atoms (Avogadro's number)
Now we can find how many moles of platinum are in 195.08 grams:
195.08 grams * (1 mole / 195.08 grams) = 1 mole
So, there is 1 mole of platinum in 195.08 grams.
Now, we can find how many atoms of platinum are in 1 mole:
1 mole * (6.022 x 10^23 atoms / 1 mole) = 6.022 x 10^23 atoms
Therefore, there are 6.022 x 10^23 atoms of platinum in 195.08 grams.
Therefore, the correct answer is B. 6.022 x 10^23 atoms.