Question

When Uranium-238 (^{238}{92}U) undergoes alpha decay, it forms Thorium-234 (^{234}{90}Th) and an alpha particle (^{4}_{2}He). The alpha particle is essentially a helium nucleus, containing 2 protons and 2 neutrons1. So, the nuclear equation for this decay process is:

Answer 1

[AI-generated answer — Bot GPT 3.5]

^{238}_{92}U → ^{234}_{90}Th + ^{4}_{2}He.