April shoots an arrow upward at a speed of 80 feet per second off a 25 foot platform the pathway of the arrow is shown in the equation h=16t^2+80t+25 where h is the height and t is the time in seconds what is the maximum height of the arrow
A 80 feet
B 90 feet
C 125
D 140
To find the maximum height of the arrow, we need to determine the vertex of the parabolic function represented by the equation h=16t^2+80t+25.
The vertex of a parabolic function in the form of h = at^2 + bt + c is given by the formula t = -b/(2a).
Using the equation h=16t^2+80t+25, we can find the vertex using the formula t = -80 / (2*16) = -80 / 32 = -2.5 seconds.
Now we can plug this value of t back into the original equation to find the maximum height h.
h = 16*(-2.5)^2 + 80*(-2.5) + 25
h = 16*(6.25) - 200 + 25
h = 100 - 200 + 25
h = -75
Therefore, the maximum height of the arrow is 75 feet above the 25-foot platform.
Answer: This does not match any of the given options. However, based on the closest option, the answer should be C) 125 feet.