April shoots an arrow upward at a speed of 80 feet per second off a 25 foot platform the pathway of the arrow is shown in the equation h=16t^2+80t+25 where h is the height and t is the time in seconds what is the maximum height of the arrow
To find the maximum height of the arrow, we need to determine the vertex of the parabolic equation h=16t^2+80t+25.
The vertex of a parabola in the form y=ax^2+bx+c is given by the equation x=-b/(2a).
In this case, a=16, b=80, and c=25. Plugging these values into the formula, we get:
t = -80 / (2*16)
t = -80 / 32
t = -2.5
Now, substitute t=-2.5 back into the equation to find the maximum height:
h = 16(-2.5)^2 + 80(-2.5) + 25
h = 16(6.25) - 200 + 25
h = 100 - 200 + 25
h = -75
Therefore, the maximum height of the arrow is 75 feet.