A giant model of a magnet is being built for a museum exhibit. What is the total surface area of the prop that will need to be painted if the depth of the magnet is 3 feet?
(1 point)
Responses
180 ft.2
180 ft. squared
330 ft.2
330 ft. squared
370 ft.2
370 ft. squared
410 ft.2
The total surface area of the prop that will need to be painted can be calculated by finding the surface area of the four sides and the top and bottom of the magnet.
If the depth of the magnet is 3 feet, this means each side of the magnet is a square with dimensions 3 ft x 3 ft, so the surface area of each side is 3 ft x 3 ft = 9 ft^2.
There are four sides to the magnet, so the total surface area of the sides is 4 sides x 9 ft^2 = 36 ft^2.
The top and bottom of the magnet are also squares with dimensions 3 ft x 3 ft each, so the surface area of each is also 9 ft^2.
Therefore, the total surface area of the prop that will need to be painted is the sum of the surface area of the sides (36 ft^2) and the surface area of the top and bottom (2 x 9 ft^2).
Total surface area = 36 ft^2 + 2 x 9 ft^2 = 36 ft^2 + 18 ft^2 = 54 ft^2.
Therefore, the total surface area of the prop that will need to be painted is 54 ft^2.
None of the provided options match this calculation, so there seems to be a mistake in the question or options given.