The figure below represents a cylindrical solid whose dimensions are shown
What it the surface are of the solid whose length is 20cm and a width of 14cm with two semi circles
To find the surface area of the cylindrical solid, we need to calculate the areas of the two bases (two semi circles) and the lateral surface area.
1. The two bases are two semi circles with a diameter of 14 cm, which means the radius is half of the diameter, so the radius is 7 cm. The area of one semi circle is given by the formula A = (1/2)πr^2 = (1/2) * π * 7^2 = (1/2) * π * 49 = 24.5π cm^2. Since there are two semi circles, the total area of the bases is 2 * 24.5π = 49π cm^2.
2. The lateral surface area of a cylinder is given by the formula A = 2πrh, where r is the radius and h is the height (or length in this case) of the cylinder. In this case, r = 7 cm and h = 20 cm, so the lateral surface area is 2π * 7 * 20 = 280π cm^2.
3. Therefore, the total surface area of the cylindrical solid is the sum of the areas of the two bases and the lateral surface area: 49π + 280π = 329π cm^2.
So, the surface area of the solid is 329π cm^2.