square the binomial: (12y-5)^2
A 144y^2 + 120y - 25
B 144y^2 - 120y + 25
C 144y^2 + 25
D 144y^2 - 60y + 25
To square the binomial (12y-5)^2, we need to use the formula (a-b)^2 = a^2 - 2ab + b^2.
In this case, a = 12y and b = 5.
Therefore, (12y-5)^2 = (12y)^2 - 2(12y)(5) + (5)^2
= 144y^2 - 120y + 25
So, the answer is A) 144y^2 - 120y + 25.